(-3u+5)(3u-5)=0

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Solution for (-3u+5)(3u-5)=0 equation: 



(-3u+5)(3u-5)=0

We multiply parentheses ..

(-9u^2+15u+15u-25)=0

We get rid of parentheses

-9u^2+15u+15u-25=0

We add all the numbers together, and all the variables

-9u^2+30u-25=0

a = -9; b = 30; c = -25;
Δ = b2-4ac
Δ = 302-4·(-9)·(-25)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$u=\frac{-b}{2a}=\frac{-30}{-18}=1+2/3$

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