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(-3x+1)(3x+4)=2x+26
We move all terms to the left:
(-3x+1)(3x+4)-(2x+26)=0
We get rid of parentheses
(-3x+1)(3x+4)-2x-26=0
We multiply parentheses ..
(-9x^2-12x+3x+4)-2x-26=0
We get rid of parentheses
-9x^2-12x+3x-2x+4-26=0
We add all the numbers together, and all the variables
-9x^2-11x-22=0
a = -9; b = -11; c = -22;
Δ = b2-4ac
Δ = -112-4·(-9)·(-22)
Δ = -671
Delta is less than zero, so there is no solution for the equation
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