(-3x+11)(4x+18)=0

Solution for (-3x+11)(4x+18)=0 equation:

(-3x+11)(4x+18)=0

We multiply parentheses ..

(-12x^2-54x+44x+198)=0

We get rid of parentheses

-12x^2-54x+44x+198=0

We add all the numbers together, and all the variables

-12x^2-10x+198=0

a = -12; b = -10; c = +198;
Δ = b2-4ac
Δ = -102-4·(-12)·198
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9604}=98$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-98}{2*-12}=\frac{-88}{-24}
=3+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+98}{2*-12}=\frac{108}{-24}
=-4+1/2
$