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(-3x+6)(2x-10)=0
We multiply parentheses ..
(-6x^2+30x+12x-60)=0
We get rid of parentheses
-6x^2+30x+12x-60=0
We add all the numbers together, and all the variables
-6x^2+42x-60=0
a = -6; b = 42; c = -60;
Δ = b2-4ac
Δ = 422-4·(-6)·(-60)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-18}{2*-6}=\frac{-60}{-12} =+5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+18}{2*-6}=\frac{-24}{-12} =+2 $
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