(-3x/3)-(x+15/x+9)=1

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Solution for (-3x/3)-(x+15/x+9)=1 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(-3*x)/3-x-(15/x)-9 = 1 // - 1

(-3*x)/3-x-(15/x)-9-1 = 0

(-3*x)/3-x-15*x^-1-9-1 = 0

-2*x^1-15*x^-1-10*x^0 = 0

(-2*x^2-10*x^1-15*x^0)/(x^1) = 0 // * x^2

x^1*(-2*x^2-10*x^1-15*x^0) = 0

x^1

-2*x^2-10*x-15 = 0

-2*x^2-10*x-15 = 0

DELTA = (-10)^2-(-15*(-2)*4)

DELTA = -20

DELTA < 0

x in { } 

x belongs to the empty set

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