(-3z+6)+2(z+1)+z=14

Solution for (-3z+6)+2(z+1)+z=14 equation:

Simplifying
(-3z + 6) + 2(z + 1) + z = 14

Reorder the terms:
(6 + -3z) + 2(z + 1) + z = 14

Remove parenthesis around (6 + -3z)
6 + -3z + 2(z + 1) + z = 14

Reorder the terms:
6 + -3z + 2(1 + z) + z = 14
6 + -3z + (1 * 2 + z * 2) + z = 14
6 + -3z + (2 + 2z) + z = 14

Reorder the terms:
6 + 2 + -3z + 2z + z = 14

Combine like terms: 6 + 2 = 8
8 + -3z + 2z + z = 14

Combine like terms: -3z + 2z = -1z
8 + -1z + z = 14

Combine like terms: -1z + z = 0
8 + 0 = 14
8 = 14

Solving
8 = 14

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.