(-4)=1x2+3x+4

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Solution for (-4)=1x2+3x+4 equation: 



(-4)=1x^2+3x+4

We move all terms to the left:

(-4)-(1x^2+3x+4)=0

We add all the numbers together, and all the variables

-(1x^2+3x+4)-4=0

We get rid of parentheses

-1x^2-3x-4-4=0

We add all the numbers together, and all the variables

-1x^2-3x-8=0

a = -1; b = -3; c = -8;
Δ = b2-4ac
Δ = -32-4·(-1)·(-8)
Δ = -23
Delta is less than zero, so there is no solution for the equation

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