(-4)=x2+1+(-2)=3x-1

Solution for (-4)=x2+1+(-2)=3x-1 equation:

(-4)=x2+1+(-2)=3x-1

We move all terms to the left:

(-4)-(x2+1+(-2))=0

We add all the numbers together, and all the variables

-(x2+1+(-2))-4=0


We calculate terms in parentheses: -(x2+1+(-2)), so:

x2+1+(-2)

We add all the numbers together, and all the variables

x^2-1

Back to the equation:

-(x^2-1)


We get rid of parentheses

-x^2+1-4=0

We add all the numbers together, and all the variables

-1x^2-3=0

a = -1; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·(-1)·(-3)
Δ = -12
Delta is less than zero, so there is no solution for the equation