(-4+2i)(2+i)=

Solution for (-4+2i)(2+i)= equation:

Simplifying
(-4 + 2i)(2 + i) = 0

Multiply (-4 + 2i) * (2 + i)
(-4(2 + i) + 2i * (2 + i)) = 0
((2 * -4 + i * -4) + 2i * (2 + i)) = 0
((-8 + -4i) + 2i * (2 + i)) = 0
(-8 + -4i + (2 * 2i + i * 2i)) = 0
(-8 + -4i + (4i + 2i2)) = 0

Combine like terms: -4i + 4i = 0
(-8 + 0 + 2i2) = 0
(-8 + 2i2) = 0

Solving
-8 + 2i2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 2i2 = 0 + 8

Combine like terms: -8 + 8 = 0
0 + 2i2 = 0 + 8
2i2 = 0 + 8

Combine like terms: 0 + 8 = 8
2i2 = 8

Divide each side by '2'.
i2 = 4

Simplifying
i2 = 4

Take the square root of each side:
i = {-2, 2}