(-4+2y)(3-5y)=0

Solution for (-4+2y)(3-5y)=0 equation:

(-4+2y)(3-5y)=0

We add all the numbers together, and all the variables

(2y-4)(-5y+3)=0

We multiply parentheses ..

(-10y^2+6y+20y-12)=0

We get rid of parentheses

-10y^2+6y+20y-12=0

We add all the numbers together, and all the variables

-10y^2+26y-12=0

a = -10; b = 26; c = -12;
Δ = b2-4ac
Δ = 262-4·(-10)·(-12)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-14}{2*-10}=\frac{-40}{-20}
=+2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+14}{2*-10}=\frac{-12}{-20}
=3/5
$