(-4+3a)+2bi=11-12i

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Solution for (-4+3a)+2bi=11-12i equation:


Simplifying
(-4 + 3a) + 2bi = 11 + -12i

Remove parenthesis around (-4 + 3a)
-4 + 3a + 2bi = 11 + -12i

Solving
-4 + 3a + 2bi = 11 + -12i

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 3a + 4 + 2bi = 11 + 4 + -12i

Reorder the terms:
-4 + 4 + 3a + 2bi = 11 + 4 + -12i

Combine like terms: -4 + 4 = 0
0 + 3a + 2bi = 11 + 4 + -12i
3a + 2bi = 11 + 4 + -12i

Combine like terms: 11 + 4 = 15
3a + 2bi = 15 + -12i

Add '-2bi' to each side of the equation.
3a + 2bi + -2bi = 15 + -2bi + -12i

Combine like terms: 2bi + -2bi = 0
3a + 0 = 15 + -2bi + -12i
3a = 15 + -2bi + -12i

Divide each side by '3'.
a = 5 + -0.6666666667bi + -4i

Simplifying
a = 5 + -0.6666666667bi + -4i

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