(-4+4i)(-3-3i)=0

Solution for (-4+4i)(-3-3i)=0 equation:

Simplifying
(-4 + 4i)(-3 + -3i) = 0

Multiply (-4 + 4i) * (-3 + -3i)
(-4(-3 + -3i) + 4i * (-3 + -3i)) = 0
((-3 * -4 + -3i * -4) + 4i * (-3 + -3i)) = 0
((12 + 12i) + 4i * (-3 + -3i)) = 0
(12 + 12i + (-3 * 4i + -3i * 4i)) = 0
(12 + 12i + (-12i + -12i2)) = 0

Combine like terms: 12i + -12i = 0
(12 + 0 + -12i2) = 0
(12 + -12i2) = 0

Solving
12 + -12i2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + -12i2 = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -12i2 = 0 + -12
-12i2 = 0 + -12

Combine like terms: 0 + -12 = -12
-12i2 = -12

Divide each side by '-12'.
i2 = 1

Simplifying
i2 = 1

Take the square root of each side:
i = {-1, 1}