(-4/3)(n-6)=12

Solution for (-4/3)(n-6)=12 equation:

(-4/3)(n-6)=12

We move all terms to the left:

(-4/3)(n-6)-(12)=0


Domain of the equation: 3)(n-6)!=0

n∈R


We multiply parentheses ..

(-4n^2-4/3*-6)-12=0

We multiply all the terms by the denominator


(-4n^2-4-12*3*-6)=0

We get rid of parentheses

-4n^2-4-6-12*3*=0

We add all the numbers together, and all the variables

-4n^2=0

a = -4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-4)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{-8}=0$