(-4/3)x+5/3=(-3/4)x-5

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Solution for (-4/3)x+5/3=(-3/4)x-5 equation: 



(-4/3)x+5/3=(-3/4)x-5

We move all terms to the left:

(-4/3)x+5/3-((-3/4)x-5)=0



Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 4)x-5)!=0

x!=0/1

x!=0

x∈R



We multiply parentheses

-4x^2-((-3/4)x-5)+5/3=0

We calculate fractions


-4x^2+()/4x-5)*3)+20x/4x-5)*3)=0

We calculate fractions


-4x^2+(()*4x)/16x^2+(-5)*3)+20x*4x)/16x^2=0

We multiply all the terms by the denominator


-4x^2*16x^2+(()*4x)+(-5)*3)+20x*4x)=0



We calculate terms in parentheses: +(()*4x), so:

()*4x



Wy multiply elements

-64x^4+(()*4x)+(-5)*3)+20x*4x)=0

We get rid of parentheses

-64x^4+(()*4x)-5)*3)+20x*4x=0



We calculate terms in parentheses: +(()*4x), so:

()*4x



We do not support expression: x^4

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