(-4/y+2)=-6-(5/y-1)

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Solution for (-4/y+2)=-6-(5/y-1) equation: 



(-4/y+2)=-6-(5/y-1)

We move all terms to the left:

(-4/y+2)-(-6-(5/y-1))=0



Domain of the equation: y+2)!=0

y∈R





Domain of the equation: y-1))!=0

y∈R



We get rid of parentheses

-4/y-(-6-(5/y-1))+2=0

We calculate fractions


(-4y)/y^2+(-(-6-(5*y)/y^2+2=0

We add all the numbers together, and all the variables

(-4y)/y^2+(-(-6-(+5y)/y^2+2=0

We calculate fractions

We do not support eypression: y^4

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