(-4q-5)=3(-q+2)

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Solution for (-4q-5)=3(-q+2) equation:



(-4q-5)=3(-q+2)
We move all terms to the left:
(-4q-5)-(3(-q+2))=0
We add all the numbers together, and all the variables
(-4q-5)-(3(-1q+2))=0
We get rid of parentheses
-4q-(3(-1q+2))-5=0
We calculate terms in parentheses: -(3(-1q+2)), so:
3(-1q+2)
We multiply parentheses
-3q+6
Back to the equation:
-(-3q+6)
We get rid of parentheses
-4q+3q-6-5=0
We add all the numbers together, and all the variables
-1q-11=0
We move all terms containing q to the left, all other terms to the right
-q=11
q=11/-1
q=-11

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