(-4x+1)(-2x+2)=8(x)*2

Solution for (-4x+1)(-2x+2)=8(x)*2 equation:

(-4x+1)(-2x+2)=8(x)*2

We move all terms to the left:

(-4x+1)(-2x+2)-(8(x)*2)=0

We add all the numbers together, and all the variables

(-4x+1)(-2x+2)-(+8x*2)=0

We get rid of parentheses

(-4x+1)(-2x+2)-8x*2=0

We multiply parentheses ..

(+8x^2-8x-2x+2)-8x*2=0

Wy multiply elements

(+8x^2-8x-2x+2)-16x=0

We get rid of parentheses

8x^2-8x-2x-16x+2=0

We add all the numbers together, and all the variables

8x^2-26x+2=0

a = 8; b = -26; c = +2;
Δ = b2-4ac
Δ = -262-4·8·2
Δ = 612
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{612}=\sqrt{36*17}=\sqrt{36}*\sqrt{17}=6\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-6\sqrt{17}}{2*8}=\frac{26-6\sqrt{17}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+6\sqrt{17}}{2*8}=\frac{26+6\sqrt{17}}{16}
$