(-4x+2)(4x+2)=0

Solution for (-4x+2)(4x+2)=0 equation:

(-4x+2)(4x+2)=0

We multiply parentheses ..

(-16x^2-8x+8x+4)=0

We get rid of parentheses

-16x^2-8x+8x+4=0

We add all the numbers together, and all the variables

-16x^2+4=0

a = -16; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·(-16)·4
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16}{2*-16}=\frac{-16}{-32}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16}{2*-16}=\frac{16}{-32}
=-1/2
$