(-4x+5)(6x+4)=0

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Solution for (-4x+5)(6x+4)=0 equation:



(-4x+5)(6x+4)=0
We multiply parentheses ..
(-24x^2-16x+30x+20)=0
We get rid of parentheses
-24x^2-16x+30x+20=0
We add all the numbers together, and all the variables
-24x^2+14x+20=0
a = -24; b = 14; c = +20;
Δ = b2-4ac
Δ = 142-4·(-24)·20
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-46}{2*-24}=\frac{-60}{-48} =1+1/4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+46}{2*-24}=\frac{32}{-48} =-2/3 $

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