(-4x+63)=(x-5)(x+5)

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Solution for (-4x+63)=(x-5)(x+5) equation: 



(-4x+63)=(x-5)(x+5)

We move all terms to the left:

(-4x+63)-((x-5)(x+5))=0

We use the square of the difference formula

x^2+(-4x+63)+25=0

We get rid of parentheses

x^2-4x+63+25=0

We add all the numbers together, and all the variables

x^2-4x+88=0

a = 1; b = -4; c = +88;
Δ = b2-4ac
Δ = -42-4·1·88
Δ = -336
Delta is less than zero, so there is no solution for the equation

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