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(-4x-6)(3x+4)=0
We multiply parentheses ..
(-12x^2-16x-18x-24)=0
We get rid of parentheses
-12x^2-16x-18x-24=0
We add all the numbers together, and all the variables
-12x^2-34x-24=0
a = -12; b = -34; c = -24;
Δ = b2-4ac
Δ = -342-4·(-12)·(-24)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-2}{2*-12}=\frac{32}{-24} =-1+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+2}{2*-12}=\frac{36}{-24} =-1+1/2 $
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