(-4y+9)(-2y+2)=0

Solution for (-4y+9)(-2y+2)=0 equation:

(-4y+9)(-2y+2)=0

We multiply parentheses ..

(+8y^2-8y-18y+18)=0

We get rid of parentheses

8y^2-8y-18y+18=0

We add all the numbers together, and all the variables

8y^2-26y+18=0

a = 8; b = -26; c = +18;
Δ = b2-4ac
Δ = -262-4·8·18
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-10}{2*8}=\frac{16}{16}
=1
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+10}{2*8}=\frac{36}{16}
=2+1/4
$