(-5/(4u-12))+1=(6/(u-3))

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Solution for (-5/(4u-12))+1=(6/(u-3)) equation:


D( u )

u-3 = 0

4*u-12 = 0

u-3 = 0

u-3 = 0

u-3 = 0 // + 3

u = 3

4*u-12 = 0

4*u-12 = 0

4*u-12 = 0 // + 12

4*u = 12 // : 4

u = 12/4

u = 3

u in (-oo:3) U (3:+oo)

1-5/(4*u-12) = 6/(u-3) // - 6/(u-3)

1-5/(4*u-12)-(6/(u-3)) = 0

1-5/(4*u-12)-6*(u-3)^-1 = 0

1-5/(4*u-12)-6/(u-3) = 0

(-5*(u-3))/((4*u-12)*(u-3))+(-6*(4*u-12))/((4*u-12)*(u-3))+(1*(4*u-12)*(u-3))/((4*u-12)*(u-3)) = 0

1*(4*u-12)*(u-3)-5*(u-3)-6*(4*u-12) = 0

4*u^2-29*u-24*u+36+87 = 0

4*u^2-53*u+123 = 0

4*u^2-53*u+123 = 0

4*u^2-53*u+123 = 0

DELTA = (-53)^2-(4*4*123)

DELTA = 841

DELTA > 0

u = (841^(1/2)+53)/(2*4) or u = (53-841^(1/2))/(2*4)

u = 41/4 or u = 3

(u-3)*(u-41/4) = 0

((u-3)*(u-41/4))/((4*u-12)*(u-3)) = 0

((u-3)*(u-41/4))/((4*u-12)*(u-3)) = 0 // * (4*u-12)*(u-3)

(u-3)*(u-41/4) = 0

( u-3 )

u-3 = 0 // + 3

u = 3

( u-41/4 )

u-41/4 = 0 // + 41/4

u = 41/4

u in { 3}

u = 41/4

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