(-5/2x-6)+1=(-7/x-3)

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Solution for (-5/2x-6)+1=(-7/x-3) equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(-5/2)*x-6+1 = -7/x-3 // + -7/x-3

(-5/2)*x-(-7/x)-6+1+3 = 0

(-5/2)*x+7*x^-1-6+1+3 = 0

7*x^-1-5/2*x^1-2*x^0 = 0

(7*x^0-5/2*x^2-2*x^1)/(x^1) = 0 // * x^2

x^1*(7*x^0-5/2*x^2-2*x^1) = 0

x^1

(-5/2)*x^2-2*x+7 = 0

(-5/2)*x^2-2*x+7 = 0

DELTA = (-2)^2-(4*7*(-5/2))

DELTA = 74

DELTA > 0

x = (74^(1/2)+2)/(2*(-5/2)) or x = (2-74^(1/2))/(2*(-5/2))

x = (74^(1/2)+2)/(-5) or x = (2-74^(1/2))/(-5)

x in { (74^(1/2)+2)/(-5), (2-74^(1/2))/(-5)}

x in { (74^(1/2)+2)/(-5), (2-74^(1/2))/(-5) }

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