(-5/3(x-3))+(4/x-3)=5/6

Solution for (-5/3(x-3))+(4/x-3)=5/6 equation:

(-5/3(x-3))+(4/x-3)=5/6

We move all terms to the left:

(-5/3(x-3))+(4/x-3)-(5/6)=0


Domain of the equation: 3(x-3))!=0

x∈R



Domain of the equation: x-3)!=0

x∈R


We add all the numbers together, and all the variables

(-5/3(x-3))+(4/x-3)-(+5/6)=0

We get rid of parentheses

(-5/3(x-3))+4/x-3-5/6=0

We calculate fractions


(-15x^2x/(3(x-3))*x*6)+((-5*x*6)/(3(x-3))*x*6)+(72xx/(3(x-3))*x*6)-3=0


We calculate terms in parentheses: +(-15x^2x/(3(x-3))*x*6), so:

-15x^2x/(3(x-3))*x*6

We multiply all the terms by the denominator


-15x^2x

Back to the equation:

+(-15x^2x)



We calculate terms in parentheses: +((-5*x*6)/(3(x-3))*x*6), so:

(-5*x*6)/(3(x-3))*x*6

We multiply all the terms by the denominator


(-5*x*6)

We get rid of parentheses

-5*x*6

Wy multiply elements

-30x*6

Wy multiply elements

-180x

Back to the equation:

+(-180x)



We calculate terms in parentheses: +(72xx/(3(x-3))*x*6), so:

72xx/(3(x-3))*x*6

We multiply all the terms by the denominator


72xx

Back to the equation:

+(72xx)


We get rid of parentheses

-15x^2x-180x+72xx-3=0

We move all terms containing x to the left, all other terms to the right

-15x^2x-180x+72xx=3