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(-5/3)x=-25
We move all terms to the left:
(-5/3)x-(-25)=0
Domain of the equation: 3)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(-5/3)x+25=0
We multiply parentheses
-5x^2+25=0
a = -5; b = 0; c = +25;
Δ = b2-4ac
Δ = 02-4·(-5)·25
Δ = 500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{500}=\sqrt{100*5}=\sqrt{100}*\sqrt{5}=10\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{5}}{2*-5}=\frac{0-10\sqrt{5}}{-10} =-\frac{10\sqrt{5}}{-10} =-\frac{\sqrt{5}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{5}}{2*-5}=\frac{0+10\sqrt{5}}{-10} =\frac{10\sqrt{5}}{-10} =\frac{\sqrt{5}}{-1} $
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