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(-5/7)x+(13/14)=-(1/2)
We move all terms to the left:
(-5/7)x+(13/14)-(-(1/2))=0
Domain of the equation: 7)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(-5/7)x+(+13/14)-(-(+1/2))=0
We multiply parentheses
-5x^2+(+13/14)-(-(+1/2))=0
We get rid of parentheses
-5x^2+13/14-(-(+1/2))=0
We calculate fractions
-5x^2+()/()+()/()=0
We add all the numbers together, and all the variables
-5x^2+2=0
a = -5; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-5)·2
Δ = 40
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{40}=\sqrt{4*10}=\sqrt{4}*\sqrt{10}=2\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{10}}{2*-5}=\frac{0-2\sqrt{10}}{-10} =-\frac{2\sqrt{10}}{-10} =-\frac{\sqrt{10}}{-5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{10}}{2*-5}=\frac{0+2\sqrt{10}}{-10} =\frac{2\sqrt{10}}{-10} =\frac{\sqrt{10}}{-5} $
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