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(-5/9)s=-15
We move all terms to the left:
(-5/9)s-(-15)=0
Domain of the equation: 9)s!=0We add all the numbers together, and all the variables
s!=0/1
s!=0
s∈R
(-5/9)s+15=0
We multiply parentheses
-5s^2+15=0
a = -5; b = 0; c = +15;
Δ = b2-4ac
Δ = 02-4·(-5)·15
Δ = 300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{300}=\sqrt{100*3}=\sqrt{100}*\sqrt{3}=10\sqrt{3}$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{3}}{2*-5}=\frac{0-10\sqrt{3}}{-10} =-\frac{10\sqrt{3}}{-10} =-\frac{\sqrt{3}}{-1} $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{3}}{2*-5}=\frac{0+10\sqrt{3}}{-10} =\frac{10\sqrt{3}}{-10} =\frac{\sqrt{3}}{-1} $
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