(-5x+1)(2x+2)=0

Solution for (-5x+1)(2x+2)=0 equation:

(-5x+1)(2x+2)=0

We multiply parentheses ..

(-10x^2-10x+2x+2)=0

We get rid of parentheses

-10x^2-10x+2x+2=0

We add all the numbers together, and all the variables

-10x^2-8x+2=0

a = -10; b = -8; c = +2;
Δ = b2-4ac
Δ = -82-4·(-10)·2
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-12}{2*-10}=\frac{-4}{-20}
=1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+12}{2*-10}=\frac{20}{-20}
=-1
$