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(-5x+4)3x=-48
We move all terms to the left:
(-5x+4)3x-(-48)=0
We add all the numbers together, and all the variables
(-5x+4)3x+48=0
We multiply parentheses
-15x^2+12x+48=0
a = -15; b = 12; c = +48;
Δ = b2-4ac
Δ = 122-4·(-15)·48
Δ = 3024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3024}=\sqrt{144*21}=\sqrt{144}*\sqrt{21}=12\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12\sqrt{21}}{2*-15}=\frac{-12-12\sqrt{21}}{-30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12\sqrt{21}}{2*-15}=\frac{-12+12\sqrt{21}}{-30} $
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