(-5y-3)(2y-1)=0

Solution for (-5y-3)(2y-1)=0 equation:

(-5y-3)(2y-1)=0

We multiply parentheses ..

(-10y^2+5y-6y+3)=0

We get rid of parentheses

-10y^2+5y-6y+3=0

We add all the numbers together, and all the variables

-10y^2-1y+3=0

a = -10; b = -1; c = +3;
Δ = b2-4ac
Δ = -12-4·(-10)·3
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-11}{2*-10}=\frac{-10}{-20}
=1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+11}{2*-10}=\frac{12}{-20}
=-3/5
$