(-5y-8)(2y-2)=0

Solution for (-5y-8)(2y-2)=0 equation:

(-5y-8)(2y-2)=0

We multiply parentheses ..

(-10y^2+10y-16y+16)=0

We get rid of parentheses

-10y^2+10y-16y+16=0

We add all the numbers together, and all the variables

-10y^2-6y+16=0

a = -10; b = -6; c = +16;
Δ = b2-4ac
Δ = -62-4·(-10)·16
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-26}{2*-10}=\frac{-20}{-20}
=1
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+26}{2*-10}=\frac{32}{-20}
=-1+3/5
$