(-6+10+x+5x+2+4x)/6=(-12x+-1+15+4x+7)/5

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Solution for (-6+10+x+5x+2+4x)/6=(-12x+-1+15+4x+7)/5 equation: 



(-6+10+x+5x+2+4x)/6=(-12x+-1+15+4x+7)/5

We move all terms to the left:

(-6+10+x+5x+2+4x)/6-((-12x+-1+15+4x+7)/5)=0

We add all the numbers together, and all the variables

(10x+6)/6-((-8x+21)/5)=0

We calculate fractions


10x/()+(-((-8x+21)*6)/()=0



We calculate terms in parentheses: +(-((-8x+21)*6)/(), so:

-((-8x+21)*6)/(

We multiply all the terms by the denominator


-((-8x+21)*6)



We calculate terms in parentheses: -((-8x+21)*6), so:

(-8x+21)*6

We multiply parentheses

-48x+126

Back to the equation:

-(-48x+126)



We get rid of parentheses

48x-126

Back to the equation:

+(48x-126)



We get rid of parentheses

10x/()+48x-126=0

We multiply all the terms by the denominator


10x+48x*()-126*()=0

We add all the numbers together, and all the variables

10x+48x*()=0

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