(-6+3i)(2+8i)=0

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Solution for (-6+3i)(2+8i)=0 equation:



(-6+3i)(2+8i)=0
We add all the numbers together, and all the variables
(3i-6)(8i+2)=0
We multiply parentheses ..
(+24i^2+6i-48i-12)=0
We get rid of parentheses
24i^2+6i-48i-12=0
We add all the numbers together, and all the variables
24i^2-42i-12=0
a = 24; b = -42; c = -12;
Δ = b2-4ac
Δ = -422-4·24·(-12)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-54}{2*24}=\frac{-12}{48} =-1/4 $
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+54}{2*24}=\frac{96}{48} =2 $

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