(-6+x)(x-5)=0

Solution for (-6+x)(x-5)=0 equation:

(-6+x)(x-5)=0

We add all the numbers together, and all the variables

(x-6)(x-5)=0

We multiply parentheses ..

(+x^2-5x-6x+30)=0

We get rid of parentheses

x^2-5x-6x+30=0

We add all the numbers together, and all the variables

x^2-11x+30=0

a = 1; b = -11; c = +30;
Δ = b2-4ac
Δ = -112-4·1·30
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-1}{2*1}=\frac{10}{2}
=5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+1}{2*1}=\frac{12}{2}
=6
$