(-6-4i)(3-2i)=0

Solution for (-6-4i)(3-2i)=0 equation:

(-6-4i)(3-2i)=0

We add all the numbers together, and all the variables

(-4i-6)(-2i+3)=0

We multiply parentheses ..

(+8i^2-12i+12i-18)=0

We get rid of parentheses

8i^2-12i+12i-18=0

We add all the numbers together, and all the variables

8i^2-18=0

a = 8; b = 0; c = -18;
Δ = b2-4ac
Δ = 02-4·8·(-18)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*8}=\frac{-24}{16}
=-1+1/2
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*8}=\frac{24}{16}
=1+1/2
$