(-6/u-5)=(-3/4u-20)+2

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Solution for (-6/u-5)=(-3/4u-20)+2 equation: 


D( u )

u = 0

u = 0

u = 0

u in (-oo:0) U (0:+oo)

-6/u-5 = (-3/4)*u-20+2 // - (-3/4)*u-20+2

20-((-3/4)*u)-6/u-5-2 = 0

(3/4)*u-6/u-5-2+20 = 0

3/4*u^1-6*u^-1+13*u^0 = 0

(3/4*u^2+13*u^1-6*u^0)/(u^1) = 0 // * u^2

u^1*(3/4*u^2+13*u^1-6*u^0) = 0

u^1

(3/4)*u^2+13*u-6 = 0

(3/4)*u^2+13*u-6 = 0

DELTA = 13^2-(-6*4*(3/4))

DELTA = 187

DELTA > 0

u = (187^(1/2)-13)/(2*(3/4)) or u = (-187^(1/2)-13)/(2*(3/4))

u = 2/3*(187^(1/2)-13) or u = -2/3*(187^(1/2)+13)

u in { -2/3*(187^(1/2)+13), 2/3*(187^(1/2)-13)} 

u in { -2/3*(187^(1/2)+13), 2/3*(187^(1/2)-13) }

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