(-6i)(5i)=

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Solution for (-6i)(5i)= equation: 



(-6i)(5i)=

We move all terms to the left:

(-6i)(5i)-()=0

We add all the numbers together, and all the variables

(-6i)5i=0

We multiply parentheses

-30i^2=0

a = -30; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-30)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$i=\frac{-b}{2a}=\frac{0}{-60}=0$

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