(-6y+12)(20y-32)=92

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Solution for (-6y+12)(20y-32)=92 equation: 



(-6y+12)(20y-32)=92

We move all terms to the left:

(-6y+12)(20y-32)-(92)=0

We multiply parentheses ..

(-120y^2+192y+240y-384)-92=0

We get rid of parentheses

-120y^2+192y+240y-384-92=0

We add all the numbers together, and all the variables

-120y^2+432y-476=0

a = -120; b = 432; c = -476;
Δ = b2-4ac
Δ = 4322-4·(-120)·(-476)
Δ = -41856
Delta is less than zero, so there is no solution for the equation

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