(-6y+8)+(2y-11)=n-3

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Solution for (-6y+8)+(2y-11)=n-3 equation:


Simplifying
(-6y + 8) + (2y + -11) = n + -3

Reorder the terms:
(8 + -6y) + (2y + -11) = n + -3

Remove parenthesis around (8 + -6y)
8 + -6y + (2y + -11) = n + -3

Reorder the terms:
8 + -6y + (-11 + 2y) = n + -3

Remove parenthesis around (-11 + 2y)
8 + -6y + -11 + 2y = n + -3

Reorder the terms:
8 + -11 + -6y + 2y = n + -3

Combine like terms: 8 + -11 = -3
-3 + -6y + 2y = n + -3

Combine like terms: -6y + 2y = -4y
-3 + -4y = n + -3

Reorder the terms:
-3 + -4y = -3 + n

Add '3' to each side of the equation.
-3 + 3 + -4y = -3 + 3 + n

Combine like terms: -3 + 3 = 0
0 + -4y = -3 + 3 + n
-4y = -3 + 3 + n

Combine like terms: -3 + 3 = 0
-4y = 0 + n
-4y = n

Solving
-4y = n

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '-4'.
y = -0.25n

Simplifying
y = -0.25n

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