(-7)(d+1)-d-10=(-8)(d-3)+7

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Solution for (-7)(d+1)-d-10=(-8)(d-3)+7 equation: 



(-7)(d+1)-d-10=(-8)(d-3)+7

We move all terms to the left:

(-7)(d+1)-d-10-((-8)(d-3)+7)=0

We add all the numbers together, and all the variables

-1d+(-7)(d+1)-((-8)(d-3)+7)-10=0

We multiply parentheses ..

-1d+(-7d-7)-((-8)(d-3)+7)-10=0



We calculate terms in parentheses: -((-8)(d-3)+7), so:

(-8)(d-3)+7

We multiply parentheses ..

(-8d+24)+7

We get rid of parentheses

-8d+24+7

We add all the numbers together, and all the variables

-8d+31

Back to the equation:

-(-8d+31)



We get rid of parentheses

-1d-7d+8d-7-31-10=0

We add all the numbers together, and all the variables

-48!=0

There is no solution for this equation

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