(-7)=3(t-5)-t

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Solution for (-7)=3(t-5)-t equation: 



(-7)=3(t-5)-t

We move all terms to the left:

(-7)-(3(t-5)-t)=0

We add all the numbers together, and all the variables

-(3(t-5)-t)-7=0



We calculate terms in parentheses: -(3(t-5)-t), so:

3(t-5)-t

We add all the numbers together, and all the variables

-1t+3(t-5)

We multiply parentheses

-1t+3t-15

We add all the numbers together, and all the variables

2t-15

Back to the equation:

-(2t-15)



We get rid of parentheses

-2t+15-7=0

We add all the numbers together, and all the variables

-2t+8=0

We move all terms containing t to the left, all other terms to the right

-2t=-8

t=-8/-2

t=+4

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