(-7+9p)(7+9p)=0

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Solution for (-7+9p)(7+9p)=0 equation:



(-7+9p)(7+9p)=0
We add all the numbers together, and all the variables
(9p-7)(9p+7)=0
We use the square of the difference formula
81p^2-49=0
a = 81; b = 0; c = -49;
Δ = b2-4ac
Δ = 02-4·81·(-49)
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15876}=126$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-126}{2*81}=\frac{-126}{162} =-7/9 $
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+126}{2*81}=\frac{126}{162} =7/9 $

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