(-7/2x)-(5/2)+2x=(-17/5)

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Solution for (-7/2x)-(5/2)+2x=(-17/5) equation: 



(-7/2x)-(5/2)+2x=(-17/5)

We move all terms to the left:

(-7/2x)-(5/2)+2x-((-17/5))=0



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(-7/2x)+2x-(+5/2)-((-17/5))=0

We add all the numbers together, and all the variables

2x+(-7/2x)-(+5/2)-((-17/5))=0

We get rid of parentheses

2x-7/2x-5/2-((-17/5))=0

We calculate fractions


2x+()/100x^2+()/100x^2+(-((-17*2x*2)/100x^2=0

We multiply all the terms by the denominator


2x*100x^2+(-((-17*2x*2)+()+()=0



We calculate terms in parentheses: +(-((-17*2x*2)+()+(), so:

-((-17*2x*2)+()+(



Wy multiply elements

200x^3+(-((-17*2x*2)+()+()=0



We calculate terms in parentheses: +(-((-17*2x*2)+()+(), so:

-((-17*2x*2)+()+(



We do not support expression: x^3

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