(-7g-10)(4g-9)=0

Solution for (-7g-10)(4g-9)=0 equation:

(-7g-10)(4g-9)=0

We multiply parentheses ..

(-28g^2+63g-40g+90)=0

We get rid of parentheses

-28g^2+63g-40g+90=0

We add all the numbers together, and all the variables

-28g^2+23g+90=0

a = -28; b = 23; c = +90;
Δ = b2-4ac
Δ = 232-4·(-28)·90
Δ = 10609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10609}=103$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-103}{2*-28}=\frac{-126}{-56}
=2+1/4
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+103}{2*-28}=\frac{80}{-56}
=-1+3/7
$