(-7i)(-2i)=0

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Solution for (-7i)(-2i)=0 equation:



(-7i)(-2i)=0
We multiply parentheses ..
(+14i^2)=0
We get rid of parentheses
14i^2=0
a = 14; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·14·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$i=\frac{-b}{2a}=\frac{0}{28}=0$

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