(-7x+2)1/3=(4+3x)1/3

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Solution for (-7x+2)1/3=(4+3x)1/3 equation: 


x in (-oo:+oo)

((2-7*x)^1)/3 = ((3*x+4)^1)/3 // - ((3*x+4)^1)/3

((2-7*x)^1)/3-(((3*x+4)^1)/3) = 0

(2-7*x)/3-((3*x+4)/3) = 0

(2-7*x)/3+(-1*(3*x+4))/3 = 0

2-1*(3*x+4)-7*x = 0

-10*x-2 = 0

(-10*x-2)/3 = 0

(-10*x-2)/3 = 0 // * 3

-10*x-2 = 0

-10*x-2 = 0 // + 2

-10*x = 2 // : -10

x = 2/(-10)

x = -1/5

x = -1/5

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