(-7x/5x)+(10/5x)=10

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Solution for (-7x/5x)+(10/5x)=10 equation: 


x in (-oo:+oo)

((-7*x)/5)*x+(10/5)*x = 10 // - 10

((-7*x)/5)*x+(10/5)*x-10 = 0

2*x-7/5*x^2-10 = 0

DELTA = 2^2-(-10*(-7/5)*4)

DELTA = -52

DELTA < 0

x belongs to the empty set

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