(-8/2u+6)+2=(-4/u+3)

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Solution for (-8/2u+6)+2=(-4/u+3) equation: 


D( u )

u = 0

u = 0

u = 0

u in (-oo:0) U (0:+oo)

(-8/2)*u+2+6 = 3-4/u // - 3-4/u

(-8/2)*u-(-4/u)-3+2+6 = 0

(-8/2)*u+4*u^-1-3+2+6 = 0

4*u^-1-4*u^1+5*u^0 = 0

(5*u^1-4*u^2+4*u^0)/(u^1) = 0 // * u^2

u^1*(5*u^1-4*u^2+4*u^0) = 0

u^1

5*u-4*u^2+4 = 0

5*u-4*u^2+4 = 0

DELTA = 5^2-(-4*4*4)

DELTA = 89

DELTA > 0

u = (89^(1/2)-5)/(-4*2) or u = (-89^(1/2)-5)/(-4*2)

u = (89^(1/2)-5)/(-8) or u = (89^(1/2)+5)/8

u in { (89^(1/2)-5)/(-8), (89^(1/2)+5)/8} 

u in { (89^(1/2)-5)/(-8), (89^(1/2)+5)/8 }

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