(-8/4000)q+20=(12/4000)q

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Solution for (-8/4000)q+20=(12/4000)q equation: 



(-8/4000)q+20=(12/4000)q

We move all terms to the left:

(-8/4000)q+20-((12/4000)q)=0



Domain of the equation: 4000)q!=0

q!=0/1

q!=0

q∈R





Domain of the equation: 4000)q)!=0

q!=0/1

q!=0

q∈R



We add all the numbers together, and all the variables

(-8/4000)q-((+12/4000)q)+20=0

We multiply parentheses

-8q^2-((+12/4000)q)+20=0

We multiply all the terms by the denominator


-8q^2*4000)q)-((+20*4000)q)+12=0

We add all the numbers together, and all the variables

-8q^2*4000)q)-(80000q)+12=0

We add all the numbers together, and all the variables

-8q^2*4000)q)-80000q+12=0

Wy multiply elements

-32000q^3=0

We do not support eqpression: q^3

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